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Rothschild model in Maine: Clinton is in the lead

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The Rothschild model is included in the econometric models component of the PollyVote forecast. The model expects that Clinton will obtain 97.0% of the two-party vote share in Maine, whereas Trump will end up with 3.0%.

Putting the results in context

In general, however, don't have too much faith in the results of single econometric models, as they sometimes incorporate large errors. At the very least, one should check how a econometric model's results compare to benchmark forecasts.

Comparison to other econometric models

An average of recent econometric models in Maine has Clinton at 55.4% of the two-party vote. Compared to her numbers in the Rothschild model Clinton's econometric model average is 41.6 percentage points lower.

The Rothschild model compared with PollyVote's prediction

The results of the Rothschild model for Clinton are thus 41.9 percentage points above the combined PollyVote, which at the moment predicts a value of 55.1% in Maine. In comparison, a look at the PollyVote national prediction for Clinton indicates that the actual results are 43.9 percentage points higher.

This article was automatically generated by the PollyBot, which uses algorithms developed by AX Semantics to generate text from data stored in our API. The exact dataset underlying this particular article can be found here.

Please let us know if you find any typos, missing words, or grammatical errors. Your feedback helps us to further improve the quality of the texts.

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